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Matematika u arhitekturi 2
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Zadatak 04 - Rotacione i translatorne površi
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Zadatak 4
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Zadatak 04 - Rotacione i translatorne površi
Zadatak 4
zad4
4. zadatak
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Zadatak 4
by
Jovana Periz
- Tuesday, 13 May 2014, 9:59 PM
x=cos(3*u)*sin(u)
y=sin(3*u)*cos(u)
y=sin(sin(u))
0<=u<=4*pi
x=sin(u)
y=u
z=1
0<=u<=2*pi
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zad4
4. zadatak