Zadatak 04 - Rotacione i translatorne površi

4. zadatak

 
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4. zadatak
by Dušan Zonji - Tuesday, 13 May 2014, 9:11 PM
 

a) 

X=f(u)=cos(u^2)*3
Y=g(u)=1/8*u
Z=h(u)=2*cos(4*u+1)*cos(u)
0<=u<=2*pi
rotacija oko x ose

b)

X=f(u)=cos(u)
Y=g(u)=u
Z=h(u)=1*u
0<=U<=4*pi

X=f(v)=sin(3*v)
Y=g(v)=sin(v)-cos(2*v)
Z=h(v)v
0<=V<=2*pi