Matematika u arhitekturi 2

Zadatak 03 - Površi u prostoru

zadatak3

zadatak3

by Nikola Jankovic - Saturday, 10 May 2014, 12:27 PM

 

X=2*sin(u)*tan(v)

Y=3*cos(u)*tan(v)

Z=7*sin(u)

minU:-5 maxU:3 steps:100

minV:-6 maxU:10 steps:100

 

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