Zadatak 04 - Rotacione i translatorne površi

4. Zadatak

 
Picture of Nataša Matić
4. Zadatak
by Nataša Matić - Thursday, 8 May 2014, 7:24 PM
 

a. Sinus

Xf(u)=5*u*sin(7*u+8)*cos(u+3)

Yg(u)=4*u

Zh(u)=12+sin(6*u)

0<=U<=6*pi

Rotacija oko x ose.

 

b. Sinus

 Xf(u)==sin(u)*4

Yg(u)==2*u+sin(u)

Zh(u =sin(u)

0<=U<=2*pi

 

Xf(v)=cos(v)

Yg(v)=4

Zg(v)=2*cos(v)

0<=V<=3*pi



Picture of Jelena Radovanovic
Odgovor: 4. Zadatak
by Jelena Radovanovic - Wednesday, 4 June 2014, 10:30 AM
 

a) Rotacija
Xf(u)=8*cos(u)*9*sin(u)
Yg(u)=8*u*sin(u)
Zh(u)=9
0<=U<=4*pi
Rotacija oko X ose

b) Translacija
Xf(u)=sin(u)
Yg(u)=sin(5*u)
Zh(u)=cos(u)*5
0<=U<=pi

Xf(u)=sin(2*v)
Yg(u)=cos(v)
Zh(u)=sin(v)
0<=U<=2*pi