Zadatak 03 - Površi u prostoru

povrs u ravni

 
Picture of Emilija Isakovic
povrs u ravni
by Emilija Isakovic - Saturday, 7 June 2014, 9:24 AM
 

3D Grapher

spherical

a=sin(2*u)

b=cos(u)+tan(v)

R=4*u

U: [-5,5] (50)

V: [-10,10] (200)