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Matematika u arhitekturi 2
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Zadatak 03 - Površi u prostoru
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zadatak 3
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Zadatak 03 - Površi u prostoru
zadatak 3
Zadatak 3
Površi u prostoru - 3D Grapher
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zadatak 3
by
Christopher Nicette
- Thursday, 5 June 2014, 5:31 PM
x=sin (v)*5
y=sin (v)*cos (u) *5
z=u*4
min u=-7 max u=10 steps=400
min v=-5 max v=5 steps=10
parsi u prostoru.bmp
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Zadatak 3
Površi u prostoru - 3D Grapher