Zadatak 04 - Rotacione i translatorne površi

4

 
Picture of Katarina Despotovic
4
by Katarina Despotovic - Thursday, 5 June 2014, 10:47 AM
 

1.

x=1/3*(1+cos(2*u))*u

y=u*cos(u)

z=1

0<=u<=7*pi

rotacija oko y ose

2.

x=1/2*sin(3*u)

y=u

z=1

0<=u<=3*pi

x=sin(2/5*v)

y=1

z=v

0<=v<=7*pi