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Matematika u arhitekturi 2
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Zadatak 04 - Rotacione i translatorne površi
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zadatak 04
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Zadatak 04 - Rotacione i translatorne površi
zadatak 04
Rotacione i transaltorne povrsi
zadatak 4.
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zadatak 04
by
Nikola Popovic
- Tuesday, 27 May 2014, 8:28 AM
I x= cos(u)+2-6*u II x= sin(v)^2+cos(v/3)
Y= sin(2*u)+cos(1.8^u) y= cos(v/4)*3
Z= 4*u z= sin(v/1.8)
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Rotacione i transaltorne povrsi
zadatak 4.