Zadatak 04 - Rotacione i translatorne površi

zadatak 4.

 
Foto van Stefan Hadzi Arsenovic
zadatak 4.
door Stefan Hadzi Arsenovic - dinsdag, 20 mei 2014, 23:14
 

translacija:

x=4*sin(u)*2*sin(u)
y=u*-2*sin(u)
z=cos(u)

pi<=u<=2*pi   

rotacija oko y ose:

x=4*sin(u)*sin(u)+2*cos(v)
y=cos(u)*2*sin(u)
z=cos(u)*sin(u)*sin(u)+cos(u)

pi<=u<=2*pi    pi<=u<=2*pi  



 
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Foto van ersid mandija
Odgovor: zadatak 4.
door ersid mandija - zaterdag, 24 mei 2014, 20:56
 

1.x=sin(u)*atan(u*1/2) y=log10(u*1/6) z=log10(u*1)-cos(u*10) 0 <=u<=2*pi rotacija oko y ose

1.x=sin(u)*atan(u*1/2) y=log10(u*1/6) z=log10(u*1)-cos(u*10) 0<=u<=2*pi 2. x=cos(v) y=sin(v)*cos(v) z=2 0<=v<=2*pi



 
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