Zadatak 04 - Rotacione i translatorne površi

zadatak 4.

 
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Odgovor: zadatak 4.
by ersid mandija - Saturday, 24 May 2014, 8:56 PM
 

1.x=sin(u)*atan(u*1/2) y=log10(u*1/6) z=log10(u*1)-cos(u*10) 0 <=u<=2*pi rotacija oko y ose

1.x=sin(u)*atan(u*1/2) y=log10(u*1/6) z=log10(u*1)-cos(u*10) 0<=u<=2*pi 2. x=cos(v) y=sin(v)*cos(v) z=2 0<=v<=2*pi