Zadatak 04 - Rotacione i translatorne površi

04

 
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04
by Filip Jočić - Thursday, 15 May 2014, 12:32 AM
 

a)

rotacija oko Y ose

x=cos(2*u)*2*sin(2*u)*sin(2*u)+cos(3*u)
y=u
z=1
0<=U<=2*pi

b)

x=cos(2*u)*2*sin(2*u)*sin(2*u)+cos(3*u) / x=cos(v)

y=u / y=2*sin(v)
z=1 / z=v

0<=U<=2*pi / 0<=v<=2pi