Zadatak 04 - Rotacione i translatorne površi

zadatak 4

 
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zadatak 4
by Anka Mirkovic - Wednesday, 14 May 2014, 12:20 AM
 

X=f(u,v)    10*(sin(u)/2)

Y=g(u,v)   1.5*(2*sinh(u)*sin(v) +(2/3)*sinh(3*u))

Z=h(u,v)   2*cosh(2*u)*cos(2*v)

-1<=u <=1

-pi/2<=v <= pi/2

 

X=f(u)  u*sin(u)

Y=g(u)  u*cos(u)

Z=h(u)  1

0<=U<=4*pi

 

X=f(v)  sin(V)

Y=g(v)  1

Z=g(v)  v

O<=V<=2*pi