Zadatak 04 - Rotacione i translatorne površi

4. zadatak

 
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4. zadatak
by Ivana Milovanovic - Tuesday, 13 May 2014, 9:10 PM
 

a)

X= cos(u)*3*sin(u)

Y= u

Z= sin(u)*2*cos(u)*3

0 <= u <= 2*pi

 

b)

X= 1/2*sin(u)*cos(u)

Y= u+sin(u)

Z= 3+sin(u)

0 <=U<= 3*pi

 

X= sin(v)*cos(v)

Y= 2

Z= v

0 <=V<= 3*pi