Zadatak 04 - Rotacione i translatorne površi

4. zadatak

 
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4. zadatak
by Isidora Todorovic - Monday, 12 May 2014, 6:59 PM
 

x= 20*sin(u)*cos(9*u)

y= 4*u

z= u

4<=u<=8*pi

rotacija oko y ose

 

X=sin(u)*cos(3*u)+u

Y=cos(2*u)

Z=2

0<=U<=pi

X=cos(v)*sin(3*v)+v

Y=sin(2*v)+v

Z=3*v

0<=U<=pi