Zadatak 04 - Rotacione i translatorne površi

Zadatak 4

 
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Zadatak 4
by Sonja Pesic - Saturday, 10 May 2014, 7:47 PM
 

Sinus

Rotacije oko z ose

Xf(u)=6*sin(5*u)

Yg(u)=sin(5+u)+3

Zh(u)=6+abs(2*u)

0<=U<=6*pi

 

Kosinus

 Xf(u)=sin(6*u)*abs(u)

Yg(u)=u

Zh(u)=u

0<=U<=2*pi

 

Xf(v)=sin(v)+v

Yg(v)=1

Zg(v)=v

0<=V<=2*pi