Zadatak 03 - Površi u prostoru

3.zadatak

 
Slika dea brajoviq
Odgovor: 3.zadatak
napisao/la dea brajoviq - subota, 24. maj 2014, 21:12
 

3d Grapher a=sin(u)+sin(v) r=cos(v)-2 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20 a=sin(u)+sin(v) r=cos(v)+2 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20 a=sin(u)+sin(v) r=cos(v)-4 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20 a=sin(u)+sin(v) r=cos(v)+4 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20 a=sin(u)+sin(v) r=cos(v)-6 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20 a=sin(u)+sin(v) r=cos(v)+6 z=cos(v) min u=-10 max u=-6; min v=-10 max v=-6; steps 20