Zadatak 04 - Rotacione i translatorne površi

Zadatak 04

 
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Zadatak 04
by Minja Pantic - Saturday, 10 May 2014, 11:11 AM
 

1.

X=cos(u^2)*3
Y=u^2*cos(u)*0.6+15*sin(u)
Z=0.5

7<=u<=2*pi

rotacija oko y ose

 

2.

X=cos(u)*9*u+sin(2*u)
Y=u^2
Z=1
10<=U<=3*pi

X=2*cos(v)
Y=1
Z=v
2<=V<=4*pi