Zadatak 04 - Rotacione i translatorne površi

4. zadatak

 
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4. zadatak
by Tara Jakšić - Friday, 9 May 2014, 7:39 PM
 

Rotacija oko (x) ose.

x=(5*cos(u))*cos(v)
y=0.5*sin(u)*v*2
z=(5*cos(u))*sin(v)

0 <= u <= 2pi

 

x=(2+u*cos(u))   
y=u
z=2+u*cos(u)
x=sin(2*pi*u) 
y=sin(v)*5
z=cos(2*pi*u)+2*u