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Matematika u arhitekturi 2
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Zadatak 03 - Površi u prostoru
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Zadatak 03
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Zadatak 03 - Površi u prostoru
Zadatak 03
ZADATAK 3
zadatak 03
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Zadatak 03
by
Stevan Simovic
- Saturday, 3 May 2014, 12:58 PM
3D Grapher
x=3*cos(v)*4*sin(u)
y=4*v*u+cos(15*u)
z=16*u
min u=-3
max u=6
steps=134
min v=-3
max v=6
steps=134
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ZADATAK 3
zadatak 03